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x^2+2.3x-1659.2=0
a = 1; b = 2.3; c = -1659.2;
Δ = b2-4ac
Δ = 2.32-4·1·(-1659.2)
Δ = 6642.09
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.3)-\sqrt{6642.09}}{2*1}=\frac{-2.3-\sqrt{6642.09}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.3)+\sqrt{6642.09}}{2*1}=\frac{-2.3+\sqrt{6642.09}}{2} $
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